0=4.9x^2-12x+3.05

Solution for 0=4.9x^2-12x+3.05 equation:

0=4.9x^2-12x+3.05

We move all terms to the left:

0-(4.9x^2-12x+3.05)=0

We add all the numbers together, and all the variables

-(4.9x^2-12x+3.05)=0

We get rid of parentheses

-4.9x^2+12x-3.05=0

a = -4.9; b = 12; c = -3.05;
Δ = b2-4ac
Δ = 122-4·(-4.9)·(-3.05)
Δ = 84.22
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-\sqrt{84.22}}{2*-4.9}=\frac{-12-\sqrt{84.22}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+\sqrt{84.22}}{2*-4.9}=\frac{-12+\sqrt{84.22}}{-9.8}
$